The term x is an element of alphabets. Generally, in mathematics it is used as a variable. The variable is defined as the letter which represents a number (not only the letters, can a symbol also used as a variable). The number which is represented by the variable is called the co-efficient of that variable. In algebra, polynomials are formulated from one or more variables (such as x) and also by symbols.
Procedure of Solving for X:
State all the possibilities given.
Simplify the equation.
Isolate the variable to find its exact value
Simplify the equation to get the value of the variable.
Sample Problems:
Pro 1: Solve the following equation and find the value of x.
2x + 5 = 3
Sol : Given 2x + 5 = 3
To simplify the equation subtract 5 on both sides
2x + 5 - 5 = 3 – 5
2x = -2
Simplifying this, we get
x = 1
Pro 2: Solve the equation |2x + 5| + 3 = 5
Sol : The equation to solve is given by.
|2x + 5| + 3 = 5
Subtract 3 to both sides of the equation and simplify.
|2x + 5| = 2
|2x + 5| is equal to 2 if 2x + 5 = 2.
Simplify the above equation
2x + 5 = 2.
Isolate x and simplify
x = -3/2
Pro 3: Given the system of equations
x + y = 0
2x + 3y = 2.
Solve and find the values of x and y.
Sol : Multiply the first equation by 2.
2x + 2y = 0
2x + 3y = 2
Solve the above equation by changing the sign of the terms in second equation.
2x + 2y = 0
-2x - 3y = -2
which gives the solution
-y = -2
Therefore, y = 2
Substitute y value in first equation
x + y = 0
x + 2 = 0
Hence, x = -2
Pro 4: Solve the equation 8x^4 + 3x^2 + 4x - 5x^-1 + 2x^-3 for x = 2.
Sol : Evaluate the equation by substitute the value of x
= 8x^4 + 3x^2 + 4x - 5x^-1 + 2x^-3
= 8(2)4 + 3(2)2 + 4(2) - 5(2)-1 + 2(2)-3
= 8(16) + 12 + 8 - (5/2) + (1/4)
= 128 +12 + 8 - 2.5 + 0.025
= 145.525
Problem 4:
Pro 1: Solve the quadratic equation x^2 + 5x + 6 = 0
Sol : Given x^2 + 5x + 6 = 0
For finding the roots of the equation, factorize it using trial and error method.
x^2 + 5x + 6 = 0
(x + 2) (x + 3) = 0
Therefore the roots are
x = -2 and x = -3
Procedure of Solving for X:
State all the possibilities given.
Simplify the equation.
Isolate the variable to find its exact value
Simplify the equation to get the value of the variable.
Sample Problems:
Pro 1: Solve the following equation and find the value of x.
2x + 5 = 3
Sol : Given 2x + 5 = 3
To simplify the equation subtract 5 on both sides
2x + 5 - 5 = 3 – 5
2x = -2
Simplifying this, we get
x = 1
Pro 2: Solve the equation |2x + 5| + 3 = 5
Sol : The equation to solve is given by.
|2x + 5| + 3 = 5
Subtract 3 to both sides of the equation and simplify.
|2x + 5| = 2
|2x + 5| is equal to 2 if 2x + 5 = 2.
Simplify the above equation
2x + 5 = 2.
Isolate x and simplify
x = -3/2
Pro 3: Given the system of equations
x + y = 0
2x + 3y = 2.
Solve and find the values of x and y.
Sol : Multiply the first equation by 2.
2x + 2y = 0
2x + 3y = 2
Solve the above equation by changing the sign of the terms in second equation.
2x + 2y = 0
-2x - 3y = -2
which gives the solution
-y = -2
Therefore, y = 2
Substitute y value in first equation
x + y = 0
x + 2 = 0
Hence, x = -2
Pro 4: Solve the equation 8x^4 + 3x^2 + 4x - 5x^-1 + 2x^-3 for x = 2.
Sol : Evaluate the equation by substitute the value of x
= 8x^4 + 3x^2 + 4x - 5x^-1 + 2x^-3
= 8(2)4 + 3(2)2 + 4(2) - 5(2)-1 + 2(2)-3
= 8(16) + 12 + 8 - (5/2) + (1/4)
= 128 +12 + 8 - 2.5 + 0.025
= 145.525
Problem 4:
Pro 1: Solve the quadratic equation x^2 + 5x + 6 = 0
Sol : Given x^2 + 5x + 6 = 0
For finding the roots of the equation, factorize it using trial and error method.
x^2 + 5x + 6 = 0
(x + 2) (x + 3) = 0
Therefore the roots are
x = -2 and x = -3
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